2c^2+9c+6=9c+(-14)

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Solution for 2c^2+9c+6=9c+(-14) equation: 



2c^2+9c+6=9c+(-14)

We move all terms to the left:

2c^2+9c+6-(9c+(-14))=0



We calculate terms in parentheses: -(9c+(-14)), so:

9c+(-14)

We add all the numbers together, and all the variables

9c-14

Back to the equation:

-(9c-14)



We get rid of parentheses

2c^2+9c-9c+14+6=0

We add all the numbers together, and all the variables

2c^2+20=0

a = 2; b = 0; c = +20;
Δ = b2-4ac
Δ = 02-4·2·20
Δ = -160
Delta is less than zero, so there is no solution for the equation

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